[질문] 두점(1,1)(4,4)를지나고X축에접하는포물선의방정식구하는방법

x축에 접하므로 y=a(x-p)² (1,1)-> 1=a(1-p)² - ㉠(4,4)-> 4=a(4-p)² - ㉡㉡÷㉠:4=(4-p)²/(1-p)²∴p= 2,-2 -> ㉠에 대입a=1, 1/9∴y=(x-2)², y=1/9(x+2)²