1.x 2-루트3일때x제곱-2x-3은?2.3-루트2(분수임)---를유리화.3 루트23.루트8-루트7유리화루트8 루트74.x=2 루트3,y=2-루트3일때x분에1-y분에1의값5.(x 1)(x 3)(x-2)(x-4)안녕하세요!ㅋㅋ1번문제.-답:8-6루트3x 2=루트3이라는전제하에문제를풀어볼게요~x 2=루트3이면이항을해보면,x=루트3-2가되죠?다음은x²-2x-3을인수분해해보면요~(x-3)(x 1)이되겟죠?!다음은인수분해한(x-3)(x 1)에x=루트3-2를대입하는거죠~대입하면(루트3-2-3)(루트3-2 1)이되죠!다시정리하면(루트3-5)(루트3-1)이되구요.다음괄호를풀어주는거죠~괄호풀때용어가있었는데..까먹엇네요-_-;음음..앞에①(루트3을뒤쪽에루트3과-1에곱해주고요~-5를뒤에루트3과-1에각각곱해주는거죠!)그러면3-루트3-5루트3 5가나와요~이걸다시계산하면8-6루트3이나오게되는거죠!