[질문] ln(x+1) 적분어떻게하나요?

∫1×ln(x+1)dx=[(x+1)ln(x+1)]-∫(x+1)×1/x+1dx = [(x+1)ln(x+1)]-∫1dx = [(x+1)ln(x+1)]-[x] ∴[(x+1)ln(x+1)-x] / 지식맨을 이용해주셔서 감사합니다^^