[질문] x^2=10일때(x-3)(x+4)(x+3)(x-4)/연속하는세자얀수에서가장큰수와작은수제곱의차가40?

(x-3)(x+4)(x+3)(x-4)→(x-3)(x+3)(x+4)(x-4)로,(x²-9)(x²-16),x²=10이므로, 1*6, 답=6/연속하는3자연수,n-1,n,n+1에서(n+1)²-(n-1)²=40=4n, 즉,n=10,답:9,10,11